In H₂SO₃, the oxidation number of S is +4. True but understand why you switch thats important.....Say we want the oxidation of sulfur S in FeSO4 we first find O= 4(-2)= -8 Then Fe is +2 So.....-8+2= -6 but Sulfur does not have 6 electrons it needs six due to the inductive effect so we indicate S needs +6 rather then -6 funky I know but when you draw the lewis structures and treat all as Ionic bonds it makes sense. oxidation number of Sulphur in Ferric Sulphate 6 ===== Ferrous sulphate or Iron (II) suplhate : chemical formula: Fe SO₄ Here Iron has valency - oxidation number 2. as the ions are: Fe²⁺ SO₄²⁻ Hence the oxidation number of Sulphur will be 6 like in the case of Ferric sulphate. Different ways of displaying oxidation numbers of ethanol and acetic acid. Question 8.5 Calculate the oxidation number of sulphur, chromium and nitrogen in H2SO5,Cr2O7(2-) and NO3(-). Its simple ion, sulfide carries oxidation status -2. Since you're dealing with a polyatomic ion, you know that the sum … SO4 is 2-, oxygen is -2 each*4 = -8. In sulphur dioxide (SO 2) and hydrogen peroxide (H 2 O 2), the oxidation states of sulphur and oxygen are +4 and -1 respectively.As these can increase as well as decrease when the compounds take part in chemical reactions, hence they can act as oxidising as well as reducing agents. Figure 1. Atomic sulfur has oxidation number of 0. Charge of sulfur in FeSO4 is +6 S = -2 + 8. In H₂S, the oxidation number of S is -2. Bonds between atoms of the same element (homonuclear bonds) are always divided equally. Learn more about oxidation number. The oxidation state of sulfur can thus be determined by looking at the oxidation states of the two other elements that make up the hydrogen sulfate anion, hydrogen and oxygen. In S₈, the oxidation number of S is 0. The sulfur in potash alum occurs in sulfate ions, which have the formula SO4-2. S = 6. This ion is more properly named the sulfate(IV) ion. In Na₂S₂O₃, the oxidation number of S is +2. Thus the oxidation number for is calculated as 0, as it is a neutral compound. Sulfur doesn`t have a set oxidation number and varies most of the time. What is the oxidation number of sulphur in ferric sulphate and ferrous sulphate . The sulfite ion is SO 3 2-. S + 4(-2) = -2. of -2, and that alkali metals and alkali earth metals have oxidation numbers corresponding to their charges. The -ate ending indicates that the sulfur is in a negative ion. The oxidation number of each atom can be calculated by subtracting the sum of lone pairs and electrons it gains from bonds from the number of valence electrons. S + -8 = -2. The oxidation state of the sulfur is +4. For example, In H₂SO₄, the oxidation number of S is +6. +2 because the ion so4^2-, Sulphur has +6and oxygen has - 2 so you get fe as +2 While forming numerous compounds, the oxidation number of sulfur can vary form -2 to +6. In Na₂S₂O₆, the oxidation number of S is +5. ); therefore, the ion is more properly named the sulfate (VI) ion. It will be 6. +6 Sodium hydrogen sulfate, "NaHSO"_4, is an ionic compound made up of sodium cations, "Na"^(+), and hydrogen sulfate anions, "HSO"_4^(-). The oxidation number rules state that most every time, oxygen will have an O.N. Pure element has zero oxidation number. Fe is 2+ You can set it up like this. The oxidation state of the sulfur is +6 (work it out! When forming ions it is equal the charge of ion. Potassium has a +1 charge. FeSO4 charge is neutral. The oxidation number of sulfur depends on the compound it is in. read more